Python randomly shuffles the elements in the list

Randomly shuffle the elements in the list#

Write your own function to randomly shuffle the elements in the list

Option 1: Exchange method##

Randomly select the original list index, exchange the value at the index position

import random

def random_list1(li):for i inrange(0,100):
  index1 = random.randint(0,len(li)-1)
  index2 = random.randint(0,len(li)-1)
  li[index1], li[index2]= li[index2], li[index1]return li

li =[1,2,3,4,5]
test =random_list1(li)print(test)

Option 2: Randomly select and re-add to a list##

First generate a copy of the original list a_copy, create a new empty list result, and then randomly select the values in the copy list to store in the empty list result, and then delete

import random

def random_list2(a):
 a_copy = a.copy()
 result =[]
 count =len(a)for i inrange(0, count):
  index = random.randint(0,len(a_copy)-1)
  result.append(a_copy[index])
  del a_copy[index]return result

test =[1,3,4,5,6]
result =random_list2(test)print(result)

Solution 3: The system comes with a function shuffle

import random

test =[1,2,3,4,5]
random.shuffle(test)print(test)

Python's random.shuffle() function can be used to shuffle a sequence. It shuffles the sequence itself, rather than generating a new sequence.

Attachment: shuffle function in python##

def shuffle(self, x, random=None):"""Shuffle list x in place, and return None.

 Optional argument random is a 0-argument function returning a
 random float in[0.0,1.0);if it is the default None, the
 standard random.random will be used."""

 if random is None:
  randbelow = self._randbelow
  for i inreversed(range(1,len(x))):
   # pick an element in x[:i+1]with which to exchange x[i]
   j =randbelow(i +1)
   x[i], x[j]= x[j], x[i]else:
  _ int = int
  for i inreversed(range(1,len(x))):
   # pick an element in x[:i+1]with which to exchange x[i]
   j =_int(random()*(i +1))
   x[i], x[j]= x[j], x[i]