Python implements alternate execution of two threads

I won't talk nonsense, just look at the code!

import threading
import time

def a():while True:
 lockb.acquire()print('a')
 locka.release()
 time.sleep(0.5)

def b():while True:
 locka.acquire()print('b')
 lockb.release()
 time.sleep(0.5)if __name__ =="__main__":
 locka = threading.Lock()
 lockb = threading.Lock()

 ta = threading.Thread(None, a)
 tb = threading.Thread(None, b)

 locka.acquire()   #Ensure that a is executed first

 ta.start()
 tb.start()

Acquire the other party's lock and release your own lock after running

Supplementary knowledge: thread synchronization-two threads take turns to execute python implementation

Look at the code!

import threading
import time
lockA=threading.Lock()
lockB=threading.Lock()
def printA(n):if n<0:return
 lockA.acquire()print("+++")
 lockB.release()
 time.sleep(0.1)printA(n-1)
def printB(n):if n<0:return
 lockB.acquire()print("***")
 lockA.release()
 time.sleep(0.2)printB(n-1) 
 
lockB.acquire()
t1=threading.Thread(target=printA,args=(10,))
t2=threading.Thread(target=printB,args=(10,))
t1.start()
t2.start()
t1.join()
t2.join()

Looking for an internship, I have to remember the operating system again.

Idea: Create two locks lockA and lockB. After each execution, lock your own lock and release the other party's lock.

Initially, if A runs first, the lock of A is released and the lock of B is locked.

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